Find the image of the point (3,8) with respect to the line `x+3y=7` assuming the line to be a plane mirror.

Explanation

Let line AB be` x+3y=7 `and point P be (3,8).


Let Q(h,k) be the image of point `P(3,8)` in the line `x+3y=7.`


Since line AB is a mirror,


1) Point P and Q are at equal distance from line AB, i.e., `PR=QR`, i.e., R is the mid-point of PQ.


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