Find the equation of a line drawn perpendicular to the line `x/4+y/6=1` through the point where it meets the y-axis.

Explanation

given equation of line is

`\small \frac{x}{4}+\frac{y}{6}=1`

we can rewrite it as

`3x+2y=12`

Slope of line `3x+2y=12 , m' = -\frac{3}{2}`

Let the Slope of perpendicular line is m

`m = -\frac{1}{m'}= \frac{2}{3}`

Now, the ponit of intersection

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