Find the values of ` theta ` and p, if the equation `xcostheta+ysintheta=p`is the normal form of the line `sqrt(3)x+y+2=0`.

Explanation

Given equation is `sqrt3+y+2 = 0`

Here, `a = sqrt3, b = 1`

`:. sqrt(a^2+b^2) = sqrt(3+1) = 2`

Dividing given equation by `2`,

`sqrt3/2x+1/2y +1 = 0`

`-sqrt3/2x-1/2y = 1`

Comparing this equation with , `xcostheta+ysintheta = p`

`costheta = -sqrt3/2, sintheta = -1/2 and p = 1`

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