Find the equation of the parabola that satisfies the given conditions:Vertex (0, 0), passing through (5, 2) and symmetric with respect to y–axis.

Explanation

Since the vertex is `(0,0)` and the parabola is symmetric about the y-axis. Equation of the parabola is either of the form `x^2=4ay` or `x^2=-4ay`


The parabola passes through point `(5,2)` which lies in the first quadrant


`:.` the equation of the parabola is of the form `x^2=4ay`


point `(5,2)` must satisfy the equation `x^2=4ay`


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