Find the centre and the radius of the circle `x^2+y^2+8x+10 y-8=0`.

Explanation

To find the center and the radius of the circle given by the equation \(x^2 + y^2 + 8x + 10y - 8 = 0\), we will follow these steps:

### Step 1: Rewrite the equation in standard form
The general equation of a circle is given by:
\[ x^2 + y^2 + 2gx + 2fy + c = 0 \]
We need to compare this with the given equation \(x^2 + y^2 + 8x + 10y - 8 = 0\).
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