Find the equation of the circle which passes through the points `(2,""""-2)` , and (3,4) and whose centre lies on the line `x+y=2` .

Explanation

We know that the equation of a circle with center at `(h,k)` is


`(x-h)^2+(y-k)^2=r^2`


Now, this circle passes through `(2,-2)`. Then `(2-h)^2+(-2-k)^2=r^2`


`h^2+k^2-4h+4k+8=r^2`


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