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Find the centre and radius of the circle...

Find the centre and radius of the circles`x^2+y^2-4x-8y-45=0`

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To find the center and radius of the circle given by the equation \(x^2 + y^2 - 4x - 8y - 45 = 0\), we need to rewrite the equation in the standard form of a circle. The standard form of a circle's equation is: \[ (x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center and \(r\) is the radius. ...
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