Home
Class 11
MATHS
The equation of circle having centre at ...

The equation of circle having centre at (2,2) and passes through the point (4,5) is

Text Solution

Verified by Experts

`(##_XI_11_E01_14_##)`
The center of the circle is given as `(h,k)=(2,2)`
since the circle passes through point `(4,5)` the radius `r` of the circle is the distance between the point `(2,2)` and `(4,5)`
`r=sqrt((2-4)^2+(2-5)^2)=sqrt13`
...
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTIONS

    NCERT ENGLISH|Exercise MISCELLANEOUS EXERCISE|9 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    NCERT ENGLISH|Exercise All Questions|75 Videos

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    NCERT ENGLISH|Exercise EXERCISE 12.1|4 Videos

Similar Questions

Explore conceptually related problems

Find the equation of a circle with centre (2, 2) and passes through the point (4, 5).

The equation of the circle having centre (0, 0) and passing through the point of intersection of the lines 4x + 3y = 2 and x + 2y = 3 is

Find the equation of the circle whose centre is (1,2) and which passes through the point (4,6).

Find the equation of the circle whose centre is (1,2) and which passes through the point (4,6).

Find the equation of the circle with centre (2,3) and passing through the point (2,-1).

Obtain the equation of the circle, centre (1, 0), which passes through the point P(3, 1 (1)/(2) ). Find also the equation of the equal circle which touches the given circle externally at P.

The area of the circle centred at (1,2) and passing through (4,6) is

The area of the circle centred at (1,2) and passing through (4,6) is

Find thte area of a circle, whose centre is (5, -3) and which passes through the point (-7, 2).

Circle with centre (-1,2) and passing through origin is