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(lim)(x->0)(a x+b)/(c x+1)...

`(lim)_(x->0)(a x+b)/(c x+1)`

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To find the limit of the expression \(\lim_{x \to 0} \frac{ax + b}{cx + 1}\), we can follow these steps: ### Step 1: Substitute \(x = 0\) into the expression We start by substituting \(x = 0\) into the expression to evaluate the limit directly. \[ \frac{a(0) + b}{c(0) + 1} = \frac{0 + b}{0 + 1} = \frac{b}{1} \] ...
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