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lim(x->1)(a x^2+b x+c)/(c x^2+b x+a),...

`lim_(x->1)(a x^2+b x+c)/(c x^2+b x+a),a+b+c!=0`

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To solve the limit problem \( \lim_{x \to 1} \frac{a x^2 + b x + c}{c x^2 + b x + a} \) where \( a + b + c \neq 0 \), we will follow these steps: ### Step 1: Substitute \( x = 1 \) into the function We start by substituting \( x = 1 \) into the expression: \[ \frac{a(1)^2 + b(1) + c}{c(1)^2 + b(1) + a} \] ...
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