Home
Class 11
MATHS
If each of the observation x1,x2,dotdotd...

If each of the observation `x_1,x_2,dotdotdot,x_n`is increased by a where a is a negative or positive number, show that the variance remains unchanged.

Text Solution

Verified by Experts

Let the mean of the observation `x_1,x_2,........x_n` be `barx`
variance of these observations is given by
old variance `=(1/n) sum(x_i-barx)^2`.........(1)
if each observation is increased by `a` we get new observations,
...
Promotional Banner

Topper's Solved these Questions

  • STATISTICS

    NCERT ENGLISH|Exercise EXERCISE 15.3|5 Videos
  • STATISTICS

    NCERT ENGLISH|Exercise EXERCISE 15.1|12 Videos
  • STATISTICS

    NCERT ENGLISH|Exercise EXERCISE 15.2|10 Videos
  • SETS

    NCERT ENGLISH|Exercise EXERCISE 1.5|7 Videos
  • STRAIGHT LINES

    NCERT ENGLISH|Exercise EXERCISE 10.4|4 Videos

Similar Questions

Explore conceptually related problems

If each of the observations x_(1),x_(2)….x_(n) is in - creased by k. where k positive or negative number, then show that the variance remains unchanged.

If the mean of n observations x_1,x_2,x_3...x_n is barx then the sum of deviations of observations from mean is

Let x_1, x_2, x_3, , be n values of a variable X. If these values are changed to x_1+a ,x_2+a , ....., x_n+a ,w h e r ea in R , show that the variance remains unchanged.

Mean deviation for n observation x_(1),x_(2),…..x_(n) from their mean bar x is given by

The mean of 5 observations 1,2,6,x and y is 4.4 and their variance is 8.24 , then x+y is

In a set of 2n distinct observations, each of the observations below the median of all the observations is increased by 5 and each of the remaining observation is decreased by 3 . Then the mean of the new set of observations

The number of non-negative integral solution x_1 + x_2 + x_3 + x_4 <=n (where n is a positive integer) is :

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z._-2X^(A-B) . Staements II: In alpha -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is ._z._-2X^(A-B) . Staements II: In alpha -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

Staements I: ._zX^4 undergoes 2 alpha -decays, 2 beta -decays (negative beta ) and 2 gamma -decays. As a result, the daughter product is _(z-2)X^(A-8) . Staements II: In beta -decay, the mass number decreases by 4 unit and atomic number decreases by 2 unit. In beta -decay (negative beta ), the mass number remains unchanged and atomic number increases by 1 unit. In gamma -decay, mass number and atomic number remain unchanged.

NCERT ENGLISH-STATISTICS-SOLVED EXAMPLES
  1. Calculate variance and standard deviation for the following distributi...

    Text Solution

    |

  2. Two plants A and B of a factory show following results about the numb...

    Text Solution

    |

  3. Calculate the mean, variance and standard deviation for the following...

    Text Solution

    |

  4. Find the standard deviation for the following data :5,9,8,12,6,10,6,8

    Text Solution

    |

  5. The variance of 20 observations is 5. If each observation is multiplie...

    Text Solution

    |

  6. The mean of 5 observation is 4.4 and their variance is 8.24. If three ...

    Text Solution

    |

  7. Coefficient of variation of two distributions are 60% and 70% and thei...

    Text Solution

    |

  8. The following values are calculated in respect of heights and weights ...

    Text Solution

    |

  9. If each of the observation x1,x2,dotdotdot,xnis increased by a where a...

    Text Solution

    |

  10. The mean and standard deviation of 100 observations were calculated as...

    Text Solution

    |

  11. Find the variance and standard deviation of the following data 5,12,3,...

    Text Solution

    |

  12. Find the Variance of the following data:6, 8, 10 , 12 , 14 , 16 , 18 ,...

    Text Solution

    |

  13. Find the mean deviation about the median for the following data:4,6,9,...

    Text Solution

    |

  14. Find mean deviation about the mean for the following data :xi 2 5 6 8 ...

    Text Solution

    |

  15. Calculate the mean deviation about median from the following data: 340...

    Text Solution

    |

  16. Find the mean deviation about the mean for the following data: Marks ...

    Text Solution

    |

  17. Find the mean deviation about the mean for the following data:6, 7, 10...

    Text Solution

    |

  18. Find the mean deviation about the median for the following data:3, 9, ...

    Text Solution

    |