Find the mean deviation from the mean for the following data:
38, 70, 48, 40, 42, 55, 63, 46, 54, 44

Explanation

The given data is 38,70,48,40,42,55,63,46,54,44

Mean,`barx=(38+78+48+40+42+55+63+46+54+44)/10`

`implies barx=50`

The deviations of the respective observation from the mean, `barx` i.e `x_i=barx` are `−12,20,−2,−10,−8,5,13,−4,4,−6`.

The required mean deviation about the mean is

MD=`(∑_(i=1)^10abs(x_i-barx))/10`

`implies MD=84/10=8.4`

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