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The sum and sum of squares corresponding to length `x` (in cm) and weight `y` (in gm) of 50 plant products are given below : `sum_(i=1)^(50)x_i=212 ,sum_(i=1)^(50)xi2=902. 8 ,sum_(i=1)^(50)y_i=261 ,sum_(i=1)^n y i2=1457. 6` Which is more varying the length or weight?

Text Solution

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`sum_(i=1)^(50)x_i=212 ,sum_(i=1)^(50)x_i^2=902. 8 `
Here, `N=50`
Mean `barx_i=(sum_(i=1)^(50)x_i)/N`
`=212/50`
...
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The sum and sum of squares corresponding to length x (in cm) and weight y (in gm) of 50 plant products are given below : sum_(i=1)^(50)x_i=212 ,sum_(i=1)^(50)x_i^2=902. 8 ,sum_(i=1)^(50)y_i=261 ,sum_(i=1)^50 y_ i^2=1457. 6 Which is more varying, the length or weight?

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