Find gof and fog, if `f : R ->R`and `g : R ->R`are given by `f(x) = cos x`and `g(x)=3x^2`. Show that `gof!=fog`.

Explanation

To solve the problem, we need to find the compositions of the functions \( g \) and \( f \) defined as follows:

- \( f(x) = \cos x \)
- \( g(x) = 3x^2 \)

We will find \( g \circ f \) (denoted as \( g(f(x)) \)) and \( f \circ g \) (denoted as \( f(g(x)) \)) and then show that these two compositions are not equal.

### Step 1: Find \( g \circ f \)
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