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Show that the function f: N->N given by ...

Show that the function `f: N->N` given by `f(1)=f(2)=1` and `f(x)=x-1` for every `xgeq2` , is onto but not one-one.

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Verified by Experts

We have,
`f: N → N` by `f(1) = f(2) = 1 `
and `f(x) = x - 1.`
`f` is not one-one because
...
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