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Show that the Signum function f: R->R...

Show that the Signum function `f: R->R` , given by `f(x)={1,\ if\ x >0 0,\ if\ x=0-1,\ if\ x<0` is neither one-one nor onto.

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Verified by Experts

Given`f(x)={[1 if x>0], [0 if x=0],[-1 if x< 0]}`
Foe example
`f(0)=0`
`f(-1)=-1`
...
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