Let `Y = {n^2: n in N} in N`. Consider `f : N ->Y`as `f(n)=n^2`. Show that f is invertible. Find the inverse of f.

Explanation

To solve the problem, we need to show that the function \( f : \mathbb{N} \to Y \) defined by \( f(n) = n^2 \) is invertible and then find its inverse.

### Step 1: Define the function and its codomain
The function is defined as:
\[ f(n) = n^2 \]
where \( Y = \{ n^2 : n \in \mathbb{N} \} \). This means that the codomain of \( f \) is the set of all perfect squares of natural numbers.
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