Consider `f : N ->N`, `g : N ->N`and `h : N ->R`defined as`f (x) = 2x`, `g (y) = 3y + 4`and `h (z) = sin z`, `AA`x, y and z in N. Show that ho(gof ) = (hog) of.

Explanation

To solve the problem, we need to show that \( h \circ (g \circ f) = (h \circ g) \circ f \). We will follow these steps:

### Step 1: Find \( g \circ f \)
We start with the functions defined as:
- \( f(x) = 2x \)
- \( g(y) = 3y + 4 \)

Now, we need to find \( g(f(x)) \):
...