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Let X={1,\ 2,\ 3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9...

Let `X={1,\ 2,\ 3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9}` , Let `R_1` be a relation on `X` given by `R_1={(x ,\ y): x-y` is divisible by 3} and `R_2` be another relation on `X` given by `R_2={(x ,\ y):{x ,\ y}sub{1,\ 4,\ 7}` or `{x ,\ y}sub{2,\ 5,\ 8}` or `{x ,\ y}sub{3,\ 6,\ 9}}dot` Show that `R_1=R_2` .

Text Solution

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Here, `X = {1,2,3,4,5,6,7,8,9}`
`R_1 = {(x,y): x-y` is divisible by `3}`
As, `x-y` is divisible by `3`.
`x-y = 3n` where `n in N`
`=>x= y+3n`
`y=1, x = 4` when `n=1`
`y=1, x = 7` when `n=2`
`y=4, x = 7` when `n=1`
...
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