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sin^(-1)(1-x)-2sin^(-1)x=pi/2, then x is...

`sin^(-1)(1-x)-2sin^(-1)x=pi/2`, then `x` is equal to (A) `0,1/2` (B) `1,1/2` (C) 0 (D) `1/2`

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To solve the equation \( \sin^{-1}(1-x) - 2\sin^{-1}(x) = \frac{\pi}{2} \), we can follow these steps: ### Step 1: Rearranging the Equation We start by isolating one of the terms: \[ \sin^{-1}(1-x) = \frac{\pi}{2} + 2\sin^{-1}(x) \] ...
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