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If A=[ [0,-tan((alpha)/2)],[tan(alpha/2...

If ` A=[ [0,-tan((alpha)/2)],[tan(alpha/2),0]] then (I-A)[[cosalpha,-sinalpha],[sinalpha,cosalpha]]` =

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To solve the given problem, we need to compute the expression \((I - A) \cdot B\), where \(A\) is defined as: \[ A = \begin{bmatrix} 0 & -\tan(\alpha/2) \\ \tan(\alpha/2) & 0 \end{bmatrix} \] and \(B\) is given as: ...
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NCERT ENGLISH-MATRICES-All Questions
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