Let `A=[[1,sintheta,1],[-sintheta,1,sintheta],[-1,-sintheta,1]]`, where `0lt=thetalt=2pi`. Then
(A) `D e t(A) = 0`
(B) `D e t(A) in (2,oo)`
(C) `D e t(A) in (2, 4)`
(D) `D e t (A) in [2, 4]`

Explanation

To solve the problem, we need to find the determinant of the matrix \( A \) given by:

\[
A = \begin{bmatrix}
1 & \sin \theta & 1 \\
-\sin \theta & 1 & \sin \theta \\
-1 & -\sin \theta & 1
\end{bmatrix}
...