Show that the matrix `A=[2 3 1 2]`satisfies the equation `A^2-4A+I=0`

Explanation

To show that the matrix \( A = \begin{pmatrix} 2 & 3 \\ 1 & 2 \end{pmatrix} \) satisfies the equation \( A^2 - 4A + I = 0 \), we will follow these steps:

### Step 1: Calculate \( A^2 \)

To find \( A^2 \), we multiply matrix \( A \) by itself:

\[
A^2 = A \cdot A = \begin{pmatrix} 2 & 3 \\ 1 & 2 \end{pmatrix} \cdot \begin{pmatrix} 2 & 3 \\ 1 & 2 \end{pmatrix}
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