Use product `[1-1 2 0 2-3 3-2 4]\ \ [-2 0 1 9 2-3 6 1-2]` to solve the system of equation: `x-y+2z=1` `2y-3z=1` `3x-2y+4z=2`

Explanation

given matrix are `[1-1 2 0 2-3 3-2 4][-2 0 1 9 2-3 6 1-2]`

thus, multiply both of them

`[1 0 0 0 1 0 0 0 1]`

Now, `AB=I`

thus, `A^-1=B`

`A^-1=[-2 0 1 9 2-3 6 1-2]`


From system of equation, we can say that, AX=C

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