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For what value of lambdais the function...

For what value of `lambda`is the function defined by `f(x)={{:(lambda(x^2-2x), ifxlt=0),( 4x+1, ifx >0):}` continuous at `x = 0`? What about continuity at `x = 1`?

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To determine the value of \( \lambda \) for which the function \[ f(x) = \begin{cases} \lambda(x^2 - 2x) & \text{if } x \leq 0 \\ 4x + 1 & \text{if } x > 0 \end{cases} ...
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