Is the function defined by `f(x)=x^2-sinx+5` continuous at `x=pi`?

Explanation

The given function is `f(x)=x^2-sinx+5`



At `x=pi,f(x)=f(pi)=pi^2-sinpi+5=pi^2-0+5=pi^2+5`



and `lim_(xrarrpi)f(x)=lim_(xrarrpi)(x^2-sinx+5)=pi^2-0+5=pi^2+5`



Clearly `lim_(xrarrpi)=f(pi)`



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