Find `(dy)/(dx)` in the following:`y=sec^(-1)(1/(2x^2-1))`

Explanation

To find \(\frac{dy}{dx}\) for the function \(y = \sec^{-1}\left(\frac{1}{2x^2 - 1}\right)\), we will follow these steps:

### Step 1: Rewrite the function in terms of \(\theta\)

We know that if \(y = \sec^{-1}(u)\), then \(u = \sec(\theta)\) for some angle \(\theta\). Thus, we can write:

\[
\frac{1}{2x^2 - 1} = \sec(\theta)
...