The line y=mx+1 is a tangent to the curve `y^2=4x` if the value of m is(A) 1 (B) 2(C) 3(D) 1/2.

Explanation

To find the value of \( m \) such that the line \( y = mx + 1 \) is a tangent to the curve \( y^2 = 4x \), we can follow these steps:

### Step 1: Substitute the line equation into the curve equation
We start by substituting \( y = mx + 1 \) into the curve equation \( y^2 = 4x \).

\[ (mx + 1)^2 = 4x \]
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