Let AB and CD be two vertical poles at point A and B , respectively , If AB=16 m , CD=22 m and distance between these two poles AC is 20m, then find the distance of a point R on AC such that `BR^(2)+DR^(2)` is minimum.

Explanation

Let R be a point on AB such that AR=x metres, RB=(20-x) metres


`therefore RP^2 = AR^2+AP^2=x^2+16^2`

and `RQ^2=RB^2+BQ^2`


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