Find the equation of the normal to curve `x^2=4y`which passes through the point (1, 2).

Explanation

To find the equation of the normal to the curve \( x^2 = 4y \) that passes through the point \( (1, 2) \), we can follow these steps:

### Step 1: Identify the curve and point of interest
The given curve is \( x^2 = 4y \). We need to find the normal to this curve that passes through the point \( (1, 2) \).

### Step 2: Find the slope of the normal
To find the slope of the normal, we first need to find the slope of the tangent line at a point on the curve.

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