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The slope of the tangent to the curve x=...

The slope of the tangent to the curve `x=t^2+3t-8,``y=2t^2-2t-5`at the point `(2, -1)`is(A) `(22)/7` (B) `6/7` (C) `7/6` (D) `(-6)/7`

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To find the slope of the tangent to the curve defined by the parametric equations \( x = t^2 + 3t - 8 \) and \( y = 2t^2 - 2t - 5 \) at the point \( (2, -1) \), we will follow these steps: ### Step 1: Find \( \frac{dy}{dt} \) and \( \frac{dx}{dt} \) Given: - \( x = t^2 + 3t - 8 \) - \( y = 2t^2 - 2t - 5 \) ...
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