The normal at the point (1,1) on the curve `2y+x^2=3`is
(A) `x - y = 0`
(B) `x y = 0`
(C) `x + y +1 = 0`
(D) `x y = 0`

Explanation

To find the equation of the normal at the point (1, 1) on the curve given by \(2y + x^2 = 3\), we will follow these steps:

### Step 1: Differentiate the curve to find the slope of the tangent.
The equation of the curve is:
\[ 2y + x^2 = 3 \]
To find the slope of the tangent, we need to differentiate both sides with respect to \(x\).
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