Find the point on the curve `y = (x - 2)^(2)` at which the tangent is parallel to the chord joining the points (2,0) and (4,4).

Explanation

To find the point on the curve \( y = (x - 2)^2 \) at which the tangent is parallel to the chord joining the points \( (2, 0) \) and \( (4, 4) \), we can follow these steps:

### Step 1: Find the slope of the chord
The slope of a line joining two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by the formula:
\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \]
Here, we have the points \( (2, 0) \) and \( (4, 4) \). Thus:
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