Find the equation of the tangent to the curve `y=(x-7)/((x-2)(x-3)` at the point where it cuts the x-axis.

Explanation

Given, equation of curve is `y=(x-7)/((x-2(x-3)` .........(1)


To find the intersection of given curve with x-axis


Put `y=0` in `eq(1)` we get


`0=(x-7)/((x-2(x-3)`


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