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The slope of the normal to the curve y=2...

The slope of the normal to the curve `y=2x^2+3`sin x at `x = 0`is(A) 3 (B) `1/3` (C)`-3` (D) `-1/3`

Text Solution

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Slope of normal to a curve is given as,
`m = -1/(dy/dx)`
Here, equation of the curve is,
`y = 2x^2 + 3sinx`
`=>dy/dx = 4x + 3cosx`
`:. dy/dx|_(x = 0) = 4(0)+3cos 0 = 3`
`:.` Slope of the normal ` = -1/3.`
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