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Evaluate: int(log(logx)+1/((logx)^2))dx...

Evaluate: `int(log(logx)+1/((logx)^2))dx`

Text Solution

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Given `int[log(logx)+1/((logx)^2)]dx`
`=intloglogx+int1/((logx)^2)]dx`
Integrating by parts, we get
Put `u=log(logx)=>du=1/(xlogx)dx`
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