If `d/(dx)f(x)=4x^3-3/(x^4)`such that `f(2)=0.`Then f(x) is(A) `x^4+1/(x^3)-(129)/8` (B) `x^3+1/(x^4)+(129)/8`(C) `x^4+1/(x^3)+(129)/8` (D) `x^3+1/(x^4)-(129)/8`

Explanation

To solve the problem, we need to find the function \( f(x) \) given its derivative \( \frac{d}{dx} f(x) = 4x^3 - \frac{3}{x^4} \) and the condition \( f(2) = 0 \).

### Step-by-step Solution:

1. **Integrate the Derivative**:
We start by integrating the derivative \( \frac{d}{dx} f(x) \):
\[
f(x) = \int \left( 4x^3 - \frac{3}{x^4} \right) dx
...