Find the integral`int(sqrt(x)-1/(sqrt(x)))^2dx`

Explanation

To solve the integral \(\int \left(\sqrt{x} - \frac{1}{\sqrt{x}}\right)^2 dx\), we will follow these steps:

### Step 1: Expand the integrand
Using the identity for the square of a binomial \((a - b)^2 = a^2 - 2ab + b^2\), we can expand the integrand:
\[ \left(\sqrt{x} - \frac{1}{\sqrt{x}}\right)^2 = \left(\sqrt{x}\right)^2 - 2\left(\sqrt{x}\right)\left(\frac{1}{\sqrt{x}}\right) + \left(\frac{1}{\sqrt{x}}\right)^2 \]
This simplifies to:
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