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Evaluate: int0^pi(xsinx)/(1+cos^2x)dx...

Evaluate: `int_0^pi(xsinx)/(1+cos^2x)dx`

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I = `int_0^pi (xsinx)/(1+cos^2x)dx`........(i)
also using `int_a^b f(x) dx = int_0^pi f(a+b-x) dx`
I = `int_0^pi( (pi-x)(sinx))/(1+cos^2x)dx`........(ii)
adding equation 1 and 2
2I = `pi int_0^pi (xsinx)/(1+cos^2x)dx` ...
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