Find the area of the smaller region boun...

Find the area of the smaller region bounded by the ellipse `(x^2)/9+(y^2)/4=1` and the line `x/3+y/2=1.`

Verified by Experts

First we need to find the are of eclipse
=`piab=pi*3*2=6pi`
area of first quadrent
=`1/4*6pi`
required area
=`1/4*6pi-1/2*3*2`
=`(3pi)/2-3unit^2`

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