Home
Class 12
MATHS
Find area enclosed by ellipse (x^(2))/(1...

Find area enclosed by ellipse `(x^(2))/(16) + (y^(2))/(9) = 1`

A

`10pi`

B

`11pi`

C

`12pi`

D

`13pi`

Text Solution

Verified by Experts

The correct Answer is:
C

`x^2/16+y^2/9=1`
`y^2/9=(16-x^2)/16`
`y^2=9/16(16-x^2)`
`y=pm3/4sqrt(16-x^2)`
I=`4int_0^4 ydx`
=`4int_0^4sqrt(16-x^2)`
=`3(1/2xsqrt(16-x^2)+16/2sin^(-1)x/4)_0^4`
=`3(4/2sqrt(16-16)+16/2sin^(-1)(4/4)-0-0)`
...
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    NCERT ENGLISH|Exercise EXERCISE 8.2|7 Videos
  • APPLICATION OF INTEGRALS

    NCERT ENGLISH|Exercise SOLVED EXAMPLES|15 Videos
  • APPLICATION OF DERIVATIVES

    NCERT ENGLISH|Exercise SOLVED EXAMPLES|51 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    NCERT ENGLISH|Exercise EXERCISE 5.7|17 Videos

Similar Questions

Explore conceptually related problems

Find the area enclosed by the ellipse (x^(2))/(25) + (y^(2))/(16) = 1 .

Find the area enclosed by the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 .

Number of points on the ellipse (x^(2))/(25) + (y^(2))/(16) =1 from which pair of perpendicular tangents are drawn to the ellipse (x^(2))/(16) + (y^(2))/(9) =1 is

Find area enclosed by |y|=1-x^(2) .

The minimum area of the triangle formed by the tangent to the ellipse (x^(2))/(16) + (y^(2))/(9) =1 and the co-ordinate axes is

Find the equation of the circle passing through the points of intersection of the ellipses (x^(2))/(16) + (y^(2))/(9) =1 and (x^(2))/(9) + (y^(2))/(16) =1 .

Find the equation of the tangents of the ellipse (x ^(2)) /(16) + (y ^(2))/(9) =1, which make equal intercepts on the axes.

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

The number of common tangents to the ellipse (x^(2))/(16) + (y^(2))/(9) =1 and the circle x^(2) + y^(2) = 4 is

The maximum distance of the centre of the ellipse (x^(2))/(16) +(y^(2))/(9) =1 from the chord of contact of mutually perpendicular tangents of the ellipse is