Find the general solution of the differential equations:`xlogx(dy)/(dx)+y=2/xlogx`

Explanation

Given differential equation is

`xlogx(dx)/(dy)+y=2/xlogx`

`(dy)/(dx) + (1/(xlogx))y = 2/x^2` { divided by `xlogx`}

here ` P= (1/(xlogx))` and `Q= 2/x^2`



`I.F = e^(intPdx) = e^int (1/(xlogx))dx = e^(log(logx)) = logx`

The general solution is

`y log(x) = int (2logx)/(x^2) dx +c`
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