Find the equation of the curve passing through the point (1, 1) whose differential equation is `x dy =(2x^2+1)dx(x!=0)`.

Explanation

To find the equation of the curve passing through the point (1, 1) whose differential equation is given by \( x \, dy = (2x^2 + 1) \, dx \), we will follow these steps:

### Step 1: Rewrite the differential equation
We start with the given equation:
\[ x \, dy = (2x^2 + 1) \, dx \]
Dividing both sides by \( x \) (assuming \( x \neq 0 \)):
...