Solve the differential equation `(tan^(-1)y-x)dy=(1+y^2)dx`.

Explanation

To solve the differential equation \((\tan^{-1} y - x) dy = (1 + y^2) dx\), we will follow these steps:

### Step 1: Rearranging the Equation
We start by rearranging the given equation into a more standard form. Dividing both sides by \((1 + y^2)\) and rearranging gives us:

\[ \frac{dy}{dx} = \frac{\tan^{-1} y - x}{1 + y^2} \]
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