Find the particular solution of the differential equation `(dy)/(dx)+ycotx=2x+x^2cotx(x!=0)`given that `y = 0`when `x=pi/2`.

Explanation

`dy/dx+ycotx=2x+x^2cotx`

is of the form
`dy/dy +Py=Q where P=cotx and Q=2x+x^2cotx`


`I.F=e ∫p.dx =e ∫^cotxdx`

`=e^logsinx`

`=sinx since e^logx`
=x
...