For the given differential equation , find the particular solution satisfying the given condition: `2x y+y^2-2x^2(dy)/(dx)=0; y=2`when x = 1

Explanation

To find the particular solution of the given differential equation \(2xy + y^2 - 2x^2 \frac{dy}{dx} = 0\) that satisfies the condition \(y = 2\) when \(x = 1\), we will follow these steps:

### Step 1: Rearranging the Differential Equation
We start with the given equation:
\[ 2xy + y^2 - 2x^2 \frac{dy}{dx} = 0 \]
Rearranging gives:
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