Let the vectors ` veca`and ` vecb`be such that `|veca|=3`and `| vecb|=(sqrt(2))/3`, then ` vecaxx vecb`is a unit vector, if the angle between ` veca`and ` vecb`(A) `pi//6` (B) `pi//4` (C) `pi//3` (D) `pi//2`

Explanation

To solve the problem step by step, we will use the properties of the cross product of vectors and the given magnitudes.

### Step 1: Write down the given information
We have two vectors \( \vec{a} \) and \( \vec{b} \) with the following magnitudes:
- \( |\vec{a}| = 3 \)
- \( |\vec{b}| = \frac{\sqrt{2}}{3} \)

### Step 2: Recall the formula for the magnitude of the cross product
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