Find the magnitude of two vectors ` vec a`and ` vec b` having the same magnitude and such that the angle between them is `60^0`and their scalar product is `1/2`.

Explanation

To find the magnitude of the two vectors \(\vec{a}\) and \(\vec{b}\) that have the same magnitude, an angle of \(60^\circ\) between them, and a scalar product of \(\frac{1}{2}\), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the given information**:
- Let the magnitude of both vectors be \( | \vec{a} | = | \vec{b} | = m \).
- The angle between the vectors is \( \theta = 60^\circ \).
- The scalar product (dot product) is given as \( \vec{a} \cdot \vec{b} = \frac{1}{2} \).
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