The mean of binomial distribution `B(4, (1)/(3))` is

Explanation

In the given Binomial distribution,

`n=4 and p = 1/3 and q = 1-1/3 = 2/3`


Now,`P(X=0) = 4_(C_0)p^0q^4`

`1**1**(2/3)^4 = 16/81`

`P(X=1) = 4_(C_1)p^1q^3`

`4**1/3**(2/3)^3 = 32/81`


...