A bag consists of 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0?

Explanation

`0,1,2,3,4,5,6,7,8,9`

`I-> 9/10`

`II -> 9/10`

`III -> 9/10`

`P =(9/10)(9/10)(9/10)(9/10) = (9/10)^4`

answer